document.write( "Question 1165817: Please help me in this question: A soap manufacturer decides to spend 600,000 rupees on radio, magazine and TV advertising.
\n" ); document.write( "If he spends as much on TV advertising as on magazines and radio together, and the amount
\n" ); document.write( "spent on magazines and TV combined equal five times that spent on radio, what is the amount
\n" ); document.write( "to be spent on each type of advertising? Solve by Gauss-Elimination method. \n" ); document.write( "

Algebra.Com's Answer #801881 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let T = spending on TV;  R = spending on radio and M = spending on magazines.\r\n" );
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document.write( "From the condition, we have\r\n" );
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document.write( "    T + (R + M) = 600000\r\n" );
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document.write( "    T - (R + M) = 0.\r\n" );
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document.write( "It immediately implies that  \r\n" );
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document.write( "    T = R + M = 600000/2 = 300000.     (1)\r\n" );
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document.write( "In addition, from the condition, we are given that \r\n" );
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document.write( "    T + M = 5R,    or\r\n" );
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document.write( "    300000 + M = 5R,    or\r\n" );
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document.write( "    5R - M = 300000.     (2)\r\n" );
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document.write( "So, from (1) and (2) we have\r\n" );
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document.write( "    R  + M = 300000,      (3)\r\n" );
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document.write( "    5R - M = 300000.      (4)\r\n" );
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document.write( "Add equations (3) and (4).  You will get\r\n" );
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document.write( "    6R     = 600000,\r\n" );
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document.write( "     R     = 600000/6 = 100000.\r\n" );
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document.write( "ANSWER.  R = 100000  (radio);  T = 300000 (TV)  and  M = 200000 (magazines).\r\n" );
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