document.write( "Question 1176007: A sample of 110 adults has a mean body temperature of 98.18.\r
\n" ); document.write( "\n" ); document.write( "a. Assuming that the population of healthy adults has a mean body temperature of mu = 98.6 with a standard deviation of sigma = 0.58, approximate the probability that a sample of 110 has a mean less than 98.18. (P(xBar sub 110) <= 98.18)\r
\n" ); document.write( "\n" ); document.write( "b. What if anything do the results say about the belief that the average body temperature is 98.6? \n" ); document.write( "

Algebra.Com's Answer #801867 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "Hi\r\n" );
document.write( "Normal Distribution:    μ = 98.6  and    σ = .58\r\n" );
document.write( "n = 118  x̄ = 98.16\r\n" );
document.write( " z = (98.16 - 98.6)/.58/√110 = 1.8083 |  \r\n" );
document.write( "P(x̄ < 98.16) = P(x̄ ≤ 98.16) = P(z ≤ 1.8083) = .9647\r\n" );
document.write( "\r\n" );
document.write( "b. results lend support the claim that 98.6 is the mean temperature.\r\n" );
document.write( " \r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );