document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110056>Question 110056</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\">  Hi please help me im clueless .... thank you soo muchh\r<BR>\n" );
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document.write( "First is this you have to do it with a chart <BR>\n" );
document.write( "inside wil say ratextime=distance and the equation inside with the variables.<BR>\n" );
document.write( "ok here is the problem\r<BR>\n" );
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document.write( "It takes plane 40min longer to fly from Boston to Los Angeles at 52 mi/h than it does to return at 600mi/h.  how far apart are the cities.?<BR>\n" );
document.write( "THE SECOND IS THIS \r<BR>\n" );
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document.write( "It took Cindy 2h to bike from Abbott to Benson at a constant speed.  The return trip took only 1.5h because she increased her speed by 6km/h.  How far apart are Abbott and Benson?\r<BR>\n" );
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document.write( "thank you sooo muchh <BR>\n" );
document.write( "i appreciate it i have a test on this tomorrow<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80181 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It takes plane 40min longer to fly from Boston to Los Angeles at 520 mi/h than it does to return at 600mi/h. how far apart are the cities.?<BR>\n" );
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document.write( "To LA DATA:<BR>\n" );
document.write( "Time = x+(2/3) hr ; rate = 520 mph ; distance = rt = 520[x+(2/3)]=520x+700 miles<BR>\n" );
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document.write( "To Boston DATA:<BR>\n" );
document.write( "Time = x hr  ; rate = 600 mph ; distance = 600x miles<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "distance = distance<BR>\n" );
document.write( "520x+700 = 600x<BR>\n" );
document.write( "80x = 700<BR>\n" );
document.write( "x = 8.75 hrs (time from LA to Boston)<BR>\n" );
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document.write( "600x = 5250 miles (distance between the cities)<BR>\n" );
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document.write( "Note: I changed your 52 mph rate to 520 mph<BR>\n" );
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document.write( "THE SECOND IS THIS <BR>\n" );
document.write( "It took Cindy 2h to bike from Abbott to Benson at a constant speed. The return trip took only 1.5h because she increased her speed by 6km/h. How far apart are Abbott and Benson? <BR>\n" );
document.write( "thank you sooo much <BR>\n" );
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document.write( "To Benson DATA:<BR>\n" );
document.write( "Time = 2 hrs ; rate = x kph ; distance = rt = 2x km<BR>\n" );
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document.write( "To Abbott DATA:<BR>\n" );
document.write( "Time = 1.5 hrs ; rate = (x+6) kph ; distance = rt = (3/2)(x+6) km<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "distance = distance<BR>\n" );
document.write( "2x = (3/2)x+9<BR>\n" );
document.write( "(1/2)x = 9<BR>\n" );
document.write( "x = 18 kph (rate from Abbott to Benson)<BR>\n" );
document.write( "2x=36 km (distance between Abbott and Benson)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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