document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110050>Question 110050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle.  (I need to show the equation, thanks very much.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80179 by </B><A HREF=/tutors/aboutme.mpl?userid=BrittanyM><B>BrittanyM(80)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BrittanyM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In order to solve this problem, we must begin with the formula for the perimeter:<BR>\n" );
document.write( "P=2L + 2W<BR>\n" );
document.write( "Where the legnth is twice the width plus two (L=2W+2)<BR>\n" );
document.write( "Since you know that the perimeter is 34,<BR>\n" );
document.write( "substitute 34 for P and 2W+2 for L.<BR>\n" );
document.write( "34=2(2W+2)+2W<BR>\n" );
document.write( "34=4W+4+2w<BR>\n" );
document.write( "34=6W+4<BR>\n" );
document.write( "30=6W<BR>\n" );
document.write( "w=5<BR>\n" );
document.write( "Now solve the equation for L, substituting 5 for W.<BR>\n" );
document.write( "34=2L+2(5)<BR>\n" );
document.write( "24=2L<BR>\n" );
document.write( "L=12<BR>\n" );
document.write( "So the width is 5 and the legnth is 12.  :) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );