document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992138>Question 992138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a right angled triangle the length of one of the sides forming the right angle is 4 cm more than twice the length of the other side. if the area of triangle is 120 cmsq. find its perimeter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #801779 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=801779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The legs of the triangle are x and 2x+4 cm.\r<BR>\n" );
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document.write( "(x)(2x+4) = 2 * 120\r<BR>\n" );
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document.write( "2x^2 + 4x - 240 = 0\r<BR>\n" );
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document.write( "x^2 + 2x - 120 = 0\r<BR>\n" );
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document.write( "(x+12)(x - 10) = 0\r<BR>\n" );
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document.write( "The sides are 10 cm and 24 cm, so the perimeter is 10+24+26 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50 ALIGN=MIDDLE  ALT=\"50\"   DISABLED_style= \"max-width:90%; height:auto;\" >cm. </SPAN>\n" );
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