document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1175968>Question 1175968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An isosceles right triangle has hypotenuse length x. What is the area of the triangle in terms of x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #801772 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=801772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hypotenuse length = x\r<BR>\n" );
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document.write( "side length = x/sqrt(2)\r<BR>\n" );
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document.write( "Area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2Fsqrt%282%29+%2A+x%2Fsqrt%282%29+=+x%5E2%2F2 ALIGN=MIDDLE  ALT=\"x%2Fsqrt%282%29+%2A+x%2Fsqrt%282%29+=+x%5E2%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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