document.write( "Question 1171012: The weight of a cement truck on its way to a construction site is given by W= 1200 +50m, where W is the combined weight of the truck and its contents in Ibs and m is the weight of each cubic metre of cement.\r
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document.write( "The truck must pass over a bridge with a maximum weight of 10, 000Ibs.
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document.write( "To be cost effective, the truck needs to carry at least 100m^3 per trip\r
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document.write( "Determine the possible values for W and m in this situation. \n" );
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Algebra.Com's Answer #801771 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The maximum weight of the truck on the bridge limits the amount of cement to at most 176 cubic meters. \n" ); document.write( "The cost effectiveness constraint means that the amount of cement in each load must be at least 100 cubic meters. \n" ); document.write( "ANSWERS: \n" ); document.write( "The number of cubic meters of cement can be any number from 100 to 176, inclusive. \n" ); document.write( "The weight of a truck with 100 cubic meters of cement is 1200+50(100) = 6200 pounds. The weight of a truck with 176 cubic meters of cement we already know is 10000 pounds. So the possible weights of the trucks are from 6200 pounds to 10000 pounds, inclusive. \n" ); document.write( " \n" ); document.write( " |