document.write( "Question 1107481: a) The perimeters of two similar triangles are 110 and 65. If the altitude of the smaller triangle is 5, how long is the corresponding altitude of the other triangle?\r
\n" ); document.write( "\n" ); document.write( "b) One of two similar triangles has an area 1/4 times that of the other. What is the ratio of the perimeters of the triangle?\r
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Algebra.Com's Answer #801770 by CubeyThePenguin(3113)\"\" \"About 
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a) 65/110 = 5/x\r
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\n" ); document.write( "\n" ); document.write( "x = (65 * 5)/110 = 2.954\r
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\n" ); document.write( "\n" ); document.write( "b) Without loss of generality, let the side lengths of the triangles be (3, 4, 5) and (6, 8, 10).\r
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\n" ); document.write( "\n" ); document.write( "The ratio of perimeters is \"%283%2B4%2B5%29%2F%286%2B8%2B10%29\" = 1/2
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