document.write( "Question 109975: On monday morning I had a certain amount of money. By the evening I spent half of want I had pls $3 more: on tuesday I spent half of what I had left plus $3 more: On Wenesday I spent half of what i had plus $3 more and I ended up with only $2. How much cash did I had on Monday morning? \n" ); document.write( "
Algebra.Com's Answer #80177 by BrittanyM(80)![]() ![]() ![]() You can put this solution on YOUR website! In order to solve this problem, we must work backwards.\r \n" ); document.write( "\n" ); document.write( "If on Wednesday, you had $2, \n" ); document.write( "and one day earlier you had double this plus $3, \n" ); document.write( "you would have had $7 on Tuesday. \n" ); document.write( "(this may be represented by 2x + 3, where x=2) \n" ); document.write( "And one day earlier than this, you had double plus $3, \n" ); document.write( "(2x + 3, where x=7) \n" ); document.write( "Monday afternoon, you would have had $17. \n" ); document.write( "Once more, for Monday morning, \n" ); document.write( "(2x + 3, where x=17) \n" ); document.write( "So, Monday morning, you would have had $37.\r \n" ); document.write( "\n" ); document.write( "You may check this by evaluating these values in the problem:\r \n" ); document.write( "\n" ); document.write( "1/2(37-3)=17 \n" ); document.write( "1/2(17-3)=7 \n" ); document.write( "1/2(7-3)=2 \n" ); document.write( " |