document.write( "Question 109975: On monday morning I had a certain amount of money. By the evening I spent half of want I had pls $3 more: on tuesday I spent half of what I had left plus $3 more: On Wenesday I spent half of what i had plus $3 more and I ended up with only $2. How much cash did I had on Monday morning? \n" ); document.write( "
Algebra.Com's Answer #80177 by BrittanyM(80)\"\" \"About 
You can put this solution on YOUR website!
In order to solve this problem, we must work backwards.\r
\n" ); document.write( "\n" ); document.write( "If on Wednesday, you had $2,
\n" ); document.write( "and one day earlier you had double this plus $3,
\n" ); document.write( "you would have had $7 on Tuesday.
\n" ); document.write( "(this may be represented by 2x + 3, where x=2)
\n" ); document.write( "And one day earlier than this, you had double plus $3,
\n" ); document.write( "(2x + 3, where x=7)
\n" ); document.write( "Monday afternoon, you would have had $17.
\n" ); document.write( "Once more, for Monday morning,
\n" ); document.write( "(2x + 3, where x=17)
\n" ); document.write( "So, Monday morning, you would have had $37.\r
\n" ); document.write( "\n" ); document.write( "You may check this by evaluating these values in the problem:\r
\n" ); document.write( "\n" ); document.write( "1/2(37-3)=17
\n" ); document.write( "1/2(17-3)=7
\n" ); document.write( "1/2(7-3)=2
\n" ); document.write( "
\n" );