Algebra.Com's Answer #801712 by ikleyn(52932)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "A jar contains pennies, nickels, dimes, and quarters. Without looking or feeling, you take three of the coins.
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document.write( "A) List all possible sets of three coins you might select
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document.write( "B) List all possible three coin total value you might select
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document.write( " The first sentence says \"A jar contains pennies, nickels, dimes, and quarters.\"\r
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document.write( " It does not tell, how many such coins of every type are there in the jar.\r
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document.write( " By DEFAULT, we should assume that the number of each kind of coins is LARGE ENOUGH.\r
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document.write( "If consider different triples of coins without repetition of types inside each triple, \r\n" );
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document.write( "then we have classic COMBINATIONS, and the number of such triples is  = 4.\r\n" );
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document.write( " But repetitions inside each triple ARE NOT PROHIBITED: they are allowed.\r\n" );
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document.write( "So, we should add such triples with repetitions.\r\n" );
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document.write( "Triples with repetitions are\r\n" );
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document.write( " a) (X, X, Y), where X can be any of 4 types and Y can be any of other 3 types.\r\n" );
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document.write( " In all, there are 4*3 = 12 such triples (disregarding the order inside the triples).\r\n" );
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document.write( " b) to it, we should add 4 triples of the form (X, X, X), where X can be any of 4 types.\r\n" );
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document.write( "Taking everything into account, we have, in all, 4 + 12 + 4 = 20 possible different triples (disregarding the order inside the triples).\r\n" );
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document.write( "ANSWER. there are 20 possible different triples, disregarding the order inside the triples.\r\n" );
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