document.write( "Question 1175874: The vertices of a cube of side length 2cm are connected to form a triangle as shown. What is the area of the triangle?\r
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Algebra.Com's Answer #801600 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "here you have equaterial triangle and side length is equal to the diagonal of a cube\r
\n" ); document.write( "\n" ); document.write( "if a cube of side length \"2cm\", diagonal is\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%282cm%29%5E2%2B%282cm%29%5E2%29\"
\n" ); document.write( "\"d=sqrt%284cm%5E2%2B4cm%5E2%29\"
\n" ); document.write( "\"d=sqrt%282%2A4%29cm\"
\n" ); document.write( "\"d=2sqrt%282%29cm\"\r
\n" ); document.write( "\n" ); document.write( "=> equal to the side \"a\" of a equaterial triangle\r
\n" ); document.write( "\n" ); document.write( "\"a=2sqrt%282%29cm\"\r
\n" ); document.write( "\n" ); document.write( "we need height of a triangle\r
\n" ); document.write( "\n" ); document.write( "\"h=sqrt%28a%5E2-%28a%2F2%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"h=sqrt%28%282sqrt%282%29%29%5E2-%282sqrt%282%29%2F2%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"h=sqrt%288-%288%2F4%29%29\"
\n" ); document.write( "\"h=sqrt%288-2%29\"
\n" ); document.write( "\"h=sqrt%286%29\"\r
\n" ); document.write( "\n" ); document.write( " the area of the triangle:\r
\n" ); document.write( "\n" ); document.write( "\"A=ah%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"A=%28sqrt%288%29%2Asqrt%286%29%29%2F2\"
\n" ); document.write( "\"A=2+sqrt%283%29cm%5E2\"->exact solution
\n" ); document.write( "\"A=3.46cm%5E2\"\r
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