document.write( "Question 1175839: Translate the following mathematical statements into mathematical equations and solve unknown.\r
\n" ); document.write( "\n" ); document.write( "1. The volume of gas varies directly as the temperature and inversely as the pressure. If the volume is 250 cubic centimeters when the temperature is 330°K and the pressure is 25 pounds per square centimeter, what is the volume when the temperature is 230°K and the pressure is 20 pounds per square centimeter?
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Algebra.Com's Answer #801538 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
use combined variation formula.\r
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\n" ); document.write( "\n" ); document.write( "formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "v = k * t / p\r
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\n" ); document.write( "\n" ); document.write( "v is the volume
\n" ); document.write( "k is the constant of variation
\n" ); document.write( "t is the temperature
\n" ); document.write( "p is the pressure.\r
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\n" ); document.write( "\n" ); document.write( "you are given that the volume is 250 when the temperature is 330 and the pressure is 25.\r
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\n" ); document.write( "\n" ); document.write( "use that information to solve for k.\r
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\n" ); document.write( "\n" ); document.write( "the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "250 = k * 330 / 25\r
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\n" ); document.write( "\n" ); document.write( "solve for k to get:\r
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\n" ); document.write( "\n" ); document.write( "k = 250 * 25 / 330 = 18.93939393....\r
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\n" ); document.write( "\n" ); document.write( "use that value of k to solve for v when t = 230 and p = 20.\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "v = 18.93939393..... * 230 / 20 = 217.8030303.....\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.\r
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