document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1175725>Question 1175725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice the first number plus 3 times the second number is 87. Three times the first minus <BR>\n" );
document.write( "twice the second is -6. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #801394 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=801394\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Twice the first number plus 3 times the second number is 87.<BR>\n" );
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document.write( "2a + 3b = 87 Eqn 1<BR>\n" );
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document.write( "Three times the first minus twice the second is -6. Find the numbers.<BR>\n" );
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document.write( "3a - 2b = -6 Eqn 2<BR>\n" );
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document.write( "4a + 6b = 174 Eqn 1 times 2<BR>\n" );
document.write( "9a - 6b = -18 Eqn 2 times 3<BR>\n" );
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document.write( "13a = 156<BR>\n" );
document.write( "a = 12<BR>\n" );
document.write( "etc<BR>\n" );
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