document.write( "Question 1175643: A diskette manufacturer has determined that 3% of his diskettes are defective.
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document.write( "He has just sold 2 disks to a customer.\r
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document.write( "(a) What is the probability that both the disks purchased by the customer are
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document.write( "defective? \r
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document.write( "(b) What is the probability that one of the disks is defective?\r
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document.write( "I am struggling with what Probability Methods (formulas) to use with these applications. Any help would be greatly appreciated!\r
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document.write( "Thank You!
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Algebra.Com's Answer #801293 by ikleyn(53937) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "The formulas and the numbers are\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " (a) P(both defective) = P(1st is defective)*P(2nd is defective) = 0.03*0.03 = 0.0009. ANSWER\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " (b) P(one of the two is defective) = P(1st is defective)*P(2nd is good) + P(1st is good)*P(2nd is defective) = \r\n" ); document.write( "\r\n" ); document.write( " = 0.03*(1-0.03) + (1-0.03)*0.03 = 0.0582. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |