document.write( "Question 1175634: A manufacturer makes two items,A and B. Item A requires 3 minutes of labor to assemble and B requires 4 minutes of assembly time. Item A costs $2 in raw materials and B costs $1. There is a maximum of 3,000 labor minutes available for assembly and a budget of $1,000 in raw material costs per day. Assuming they sell all the produce and that the profit is $5 per item A and $4 per item B,how many of each item must be produced in order to maximize profit? \n" ); document.write( "
Algebra.Com's Answer #801286 by ikleyn(52864)\"\" \"About 
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\n" ); document.write( "A manufacturer makes two items, A and B. Item A requires 3 minutes of labor to assemble and B requires 4 minutes of assembly time.
\n" ); document.write( "Item A costs $2 in raw materials and B costs $1. There is a maximum of 3,000 labor minutes available for assembly and a budget
\n" ); document.write( "of $1,000 in raw material costs per day. Assuming they sell all the produce and that the profit is $5 per item A and $4 per item B,
\n" ); document.write( "how many of each item must be produced in order to maximize profit?
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document.write( "Let X = # items A;  Y = # items B.\r\n" );
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document.write( "From the condition, we have this formulation of maximization problem:\r\n" );
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document.write( "    (1)  the objective function to maximize is the profit  P = 5X + 4Y  dollars.\r\n" );
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document.write( "Restrictions\r\n" );
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document.write( "    (2)  3X + 4Y <= 3000  minutes   (assembly time)\r\n" );
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document.write( "    (3)  2X +  Y <= 1000  dollars   (material cost)\r\n" );
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document.write( "    (4)   X >= 0,  Y >= 0.\r\n" );
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document.write( "You can make a plot of the feasibility domain.\r\n" );
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document.write( "It is a quadrilateral in QI with the vertices  (X,Y) = (0,0), (500,0), (200,600), (0,750).\r\n" );
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document.write( "The solution is one of these 4 points, where the objective function (profit) has a maximum.\r\n" );
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document.write( "You calculate the values of the function  P(X,Y)  at listed points\r\n" );
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document.write( "    P(0,0)                     =    0\r\n" );
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document.write( "    P(500,0)   = 5*500 + 4*0   = 2500\r\n" );
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document.write( "    P(200,600) = 5*200 + 4*600 = 3400\r\n" );
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document.write( "    P(0,750)   = 5*0   + 4*750 = 3000.\r\n" );
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document.write( "Comparing these values, you find the optimal point.\r\n" );
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document.write( "It is  (X,Y) = (200,600),  200 items A and 600 items B, providing maximum profit of 3400 dollars.\r\n" );
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\n" ); document.write( "\n" ); document.write( "In this site, there is a lesson\r
\n" ); document.write( "\n" ); document.write( "    - Solving minimax problems by the Linear Programming method \r
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