document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1175643>Question 1175643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A diskette manufacturer has determined that 3% of his diskettes are defective.<BR>\n" );
document.write( "He has just sold 2 disks to a customer.\r<BR>\n" );
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document.write( "(a) What is the probability that both the disks purchased by the customer are<BR>\n" );
document.write( "defective? \r<BR>\n" );
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document.write( "(b) What is the probability that one of the disks is defective?\r<BR>\n" );
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document.write( "I am struggling with what Probability Methods (formulas) to use with these applications.   Any help would be greatly appreciated!\r<BR>\n" );
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document.write( "Thank You!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #801283 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=801283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 97% or 0.97 of the disks are not defective<BR>\n" );
document.write( "The probability of two in a row not being defective (assuming independence) is 0.97^2=0.9409.<BR>\n" );
document.write( "probability that 1 is defective is 2*0.03*0.97=0.0582, since there are two ways that can happen.<BR>\n" );
document.write( "The sun of the first two outcomes is 0.9991, and the last possible outcome, that both disks are defective, is 0.03^2 or 0.0009, making the sum 1.0 </SPAN>\n" );
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