document.write( "Question 1175640: Mrs. Andrew’s is two years less than four times as old as her daughter Janelle. In six years Janelle will be three-eighths as old as her mother. How old is each one now? \n" ); document.write( "
Algebra.Com's Answer #801277 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "There are dozens of ways to set this problem up for solving.

\n" ); document.write( "I will show you a path to the solution that is a bit unusual but that \"works\" well for me.

\n" ); document.write( "You will probably get responses from other tutors that show more traditional algebraic solution methods.

\n" ); document.write( "\"In six years Janelle will be three-eighths as old as her mother.\"

\n" ); document.write( "With that statement, most ways of setting up the problem would involve working with fractions. I find it easier to avoid fractions, as the computations are a bit easier and faster without them.

\n" ); document.write( "So my start on the problem is this:

\n" ); document.write( "Let the ages of Mrs. Andrew and her daughter 6 years from now be 8x and 3x.

\n" ); document.write( "Then their current ages are 8x-6 and 3x-6.

\n" ); document.write( "Mrs. Andrew's age is 2 less than 4 times Janelle's age:

\n" ); document.write( "\"8x-6+=+4%283x-6%29-2\"
\n" ); document.write( "\"8x-6+=+12x-24-2+=+12x-26\"
\n" ); document.write( "\"20+=+4x\"
\n" ); document.write( "\"x+=+5\"

\n" ); document.write( "ANSWERS:
\n" ); document.write( "Mrs. Andrew's age is 8x-6 = 40-6 = 34
\n" ); document.write( "Janelle's age is 3x-6 = 9

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