document.write( "Question 1175615: Hi
\n" ); document.write( "A had 52 dollars more than B.B had 3 times as much as C. If C had 100 dollars less than A how much money did they have altogether.
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Algebra.Com's Answer #801270 by ikleyn(52835)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let C = x;\r\n" );
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document.write( "then B = 3x  and  A = 3x+52.\r\n" );
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document.write( "You are given  \r\n" );
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document.write( "    A - C = 100,  or\r\n" );
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document.write( "    (3x + 52) - x = 100,\r\n" );
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document.write( "     2x           = 100-52 = 48\r\n" );
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document.write( "      x                    = 48/2 = 24.\r\n" );
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document.write( "C had 24 dollars;  B had  3*24 = 72 dollars;  A had 72 + 52 = 124 dollars.\r\n" );
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document.write( "Together, they had   24 + 72 + 124 = 220 dollars.      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "There is special  SHARM,  when the problem solution is presented in a short form.\r
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\n" ); document.write( "\n" ); document.write( "This sharm is called  MATHEMATICAL  STYLE.\r
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