document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=109958>Question 109958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of the indicated side of triangle PQR. \r<BR>\n" );
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document.write( "1. The measure of Q= 90, measure of P=53 QR= 197, PR=? (find what PR equals) \r<BR>\n" );
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document.write( "I just need an equation to solve this using trig. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80127 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since Q=90, this is a right triangle with PR as the hypotenuse and QR the side opposite angle P\r<BR>\n" );
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document.write( "using trig, sin P=QR/PR ... so PR=QR/(sin P) ... PR=197/(sin 53) </SPAN>\n" );
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