document.write( "Question 1175582: A hospital administrator deposits $10,000 into an account that earns 9% annual interest compounded monthly. In approximately how many years will the investment be worth $18,000? Round to the nearest whole number. \n" ); document.write( "
Algebra.Com's Answer #801224 by Theo(13342)\"\" \"About 
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formula to use is f = p * (1 + r) ^ n
\n" ); document.write( "f is the future value
\n" ); document.write( "p is the present value
\n" ); document.write( "r is the interest rate per time period
\n" ); document.write( "n is the number of time periods.\r
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\n" ); document.write( "\n" ); document.write( "in this problem:\r
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\n" ); document.write( "\n" ); document.write( "f = 18,000
\n" ); document.write( "p = 10,000
\n" ); document.write( "r = 9% per year divided by 12 = .75% / 100 = .0075 per month
\n" ); document.write( "the formula requires the rate, not the percent.
\n" ); document.write( "n = what you want to find.\r
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\n" ); document.write( "\n" ); document.write( "the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "18,000 = 10,000 * 1.0075 ^ n\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 10,000 to get:\r
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\n" ); document.write( "\n" ); document.write( "1.8 = 1.0075 ^ n\r
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\n" ); document.write( "\n" ); document.write( "take the log of both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "log(1.8) = log(1.0075 ^ n)\r
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\n" ); document.write( "\n" ); document.write( "by the law of logs that says log(x^n) = n * log(x), the equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(1.8) = n * log(1.0075)\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by log(1.0075) to get:\r
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\n" ); document.write( "\n" ); document.write( "log(1.8) / log(1.0075) = n\r
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\n" ); document.write( "\n" ); document.write( "solve for n to get:\r
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\n" ); document.write( "\n" ); document.write( "n = 78.66508266 months.\r
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\n" ); document.write( "\n" ); document.write( "confirm by replacing n in the original equation and solving for f.\r
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\n" ); document.write( "\n" ); document.write( "equation becomes f = 10,000 * 1.0075 ^ 78.66508266 = 18,000.\r
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\n" ); document.write( "\n" ); document.write( "this confirms the answer is correct.\r
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\n" ); document.write( "\n" ); document.write( "divide the number of months by 12 to get 6.55542355 years.\r
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\n" ); document.write( "\n" ); document.write( "round to the nearest whole number to get 7.\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.\r
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\n" ); document.write( "\n" ); document.write( "on a graph, it looks like this.\r
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\n" ); document.write( "\n" ); document.write( "the number of years is 6.55.....\r
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\n" ); document.write( "\n" ); document.write( "that's after the end of the 6th year which puts the solution in the 7th year.\r
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