document.write( "Question 109968: Each side of a regular hexagon has length 10. Find the area of the hexagon.
\n" ); document.write( "(Hint: Divide the Hexagon into triangles)\r
\n" ); document.write( "\n" ); document.write( "How many triangles do I divide the hexagon into and what do I do from there?
\n" ); document.write( "Or just write out the equation to solve it.\r
\n" ); document.write( "\n" ); document.write( "The answer in the answer key is 150 square roots of 3.
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Algebra.Com's Answer #80120 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
There are 6 equilateral triangles in a hexagon
\n" ); document.write( "Each one is 1/6 of the area
\n" ); document.write( "Area of a triangle = a
\n" ); document.write( "\"A+=+6a\"
\n" ); document.write( "\"a+=+%281%2F2%29bh\"
\n" ); document.write( "b = 10
\n" ); document.write( "The height is the perpendicular line that bisects one of the 60 degree
\n" ); document.write( "angles of the triangle. It divides the equilateral into two
\n" ); document.write( "triangles with sides in the ratio \"1\" : \"2\" : \"sqrt%283%29\"
\n" ); document.write( "In this case, the sides are \"5\":\"10\":\"5%2Asqrt%283%29\"
\n" ); document.write( "\"a+=+%281%2F2%29bh\"
\n" ); document.write( "\"a+=+%281%2F2%2910%2A5%2Asqrt%283%29\"
\n" ); document.write( "\"a+=+25%2Asqrt%283%29\"
\n" ); document.write( "\"A+=+6a\"
\n" ); document.write( "\"A+=+6%2A25%2Asqrt%283%29\"
\n" ); document.write( "\"A+=+150%2Asqrt%283%29\" answer
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