document.write( "Question 1175529: A new virus increases exponentially at the monthly rate of 2.8%. Four months
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document.write( "after the initial outbreak, there were 10,000 reported cases. (Exponential
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document.write( "Growth)
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document.write( "a. How many were initially infected with the virus?
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document.write( "b. Model the number of reported case as a function of time. \n" );
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Algebra.Com's Answer #801159 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the formula you can use is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = p * (1 + r) ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the growth rate per time period. \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in your problem:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f is equal to 10,000 \n" ); document.write( "r is equal to .028 per month \n" ); document.write( "n is equal to 4 months.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10,000 = p * (1 + .028) ^ 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for p to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = 10,000 / (1 + .028) ^ 4 = 8954.215481.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "confirm by replacing p in the original equatio n and solving for f.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "equation becomes f = 8954.215481 * (1 + .028) ^ 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for f to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 10,000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this confirms the value of p is good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the reported cases as a function of time is f = 8954.215481 * 1.28 ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f is the future vlue. \n" ); document.write( "p is the present value which is equal to 8954.215481. \n" ); document.write( "r is equal to .028 per month. \n" ); document.write( "n is the number of months.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this equation can be graphed by replacing f with y and n with x. \n" ); document.write( "the graph is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can see that when x = 4, y = 10,000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the growth is exponential.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 36, y = 1.028^36 = 24198.01096 which is equal to 24198.011 when rounded to 3 decimal places, as shown on the graph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula is exponential because it is of the form of y = a * b ^ x, with a = 8954.215481 and b = 1.028 and x = the exponent. \n" ); document.write( " |