document.write( "Question 1175467: The high temperatures (in degrees Fahrenheit) of a random sample of 9 small towns are:
\n" ); document.write( "98.4
\n" ); document.write( "99.4
\n" ); document.write( "97.7
\n" ); document.write( "99.3
\n" ); document.write( "97.9
\n" ); document.write( "99.7
\n" ); document.write( "97.2
\n" ); document.write( "98.2
\n" ); document.write( "96.6\r
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\n" ); document.write( "\n" ); document.write( "Assume high temperatures are normally distributed. Based on this data, find the 95% confidence interval of the mean high temperature of towns. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).\r
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\n" ); document.write( "\n" ); document.write( "Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
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Algebra.Com's Answer #801113 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
document.write( "   x̄ = 98.27     s = 1.049   n = 9\r\n" );
document.write( " 95% confidence interval \r\n" );
document.write( " t = 2.31   df8\r\n" );
document.write( "ME= \"t%5Bn-1%5Ds%2Fsqrt%28n%29\" = 2.31(1.049)/3 = .81\r\n" );
document.write( "CI =  (97.46 , 99.08)\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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