document.write( "Question 1175465: Find the values of the six trigonometric functions for the angle in standard position determined by the point ​(​1,-5) \n" ); document.write( "
Algebra.Com's Answer #801104 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "We draw a right triangle with an angle in Q4, since (1,-5) is in Q4, we put x=1\r\n" );
document.write( "on the adjacent side, and y=-5 on the opposite side. \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Then we find the hypotenuse r by the Pythagorean theorem:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Since the hypotenuse r is always taken positive so we put √26 on the hypotenuse (r):\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "So now we know that\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\"tan%28X%29=opposite%2Fadjacent+=+y%2Fx=%28-5%29%2F1=-5\"\r\n" );
document.write( "\r\n" );
document.write( "\"sec%28X%29=hypotenuse%2Fopposite+=+r%2Fx=sqrt%2826%29%2F1=sqrt%2826%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"csc%28X%29=hypotenuse%2Fopposite+=+r%2Fy=sqrt%2826%29%2F%28-5%29=-sqrt%2826%29%2F5\"\r\n" );
document.write( "\r\n" );
document.write( "\"cot%28X%29=adjacent%2Fopposite+=+x%2Fy=1%2F%28-5%29=-1%2F5\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );