document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1175426>Question 1175426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half-life of a certain radioactive material is 68 hours. An initial amount of the material has a mass of 826 kg.<BR>\n" );
document.write( "Write an exponential function that models the decay of this material. Find how much radioactive material remains<BR>\n" );
document.write( "after 16 hours. Round your answer to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #801036 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=801036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If counting half-lives and x is in hours, then  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=826%2A%280.5%29%5E%28x%2F68%29 ALIGN=MIDDLE  ALT=\"y=826%2A%280.5%29%5E%28x%2F68%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > if this is the way you want your formula.\r<BR>\n" );
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document.write( "y=826(0.5)^(x/68) </SPAN>\n" );
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