document.write( "Question 1175416: A passenger train leaves a train depot 2 hours after a freight train leaves the same depot. The freight train is traveling 10 mph slower than the passenger train. Find the rate of each train if the passenger train overtakes the freight train in 3 hours. \n" ); document.write( "

Algebra.Com's Answer #801017 by VFBundy(438) $\"\"$ $\"About$

You can put this solution on YOUR website!
NOTE: I'm assuming this question is saying the passenger train catches the freight train 3 hours after the passenger train leaves. (NOT 3 hours after the freight train leaves.) That's what I'm basing the math on.
\n" ); document.write( "
\n" ); document.write( "Passenger train:
\n" ); document.write( "Distance = 3r
\n" ); document.write( "Rate = r
\n" ); document.write( "Time = 3
\n" ); document.write( "
\n" ); document.write( "Freight train:
\n" ); document.write( "Distance = 5(r - 10) = 5r - 50
\n" ); document.write( "Rate = r - 10
\n" ); document.write( "Time = 5
\n" ); document.write( "
\n" ); document.write( "5r - 50 = 3r
\n" ); document.write( "
\n" ); document.write( "2r = 50
\n" ); document.write( "
\n" ); document.write( "r = 25
\n" ); document.write( "
\n" ); document.write( "Passenger train:
\n" ); document.write( "Rate = r = 25
\n" ); document.write( "
\n" ); document.write( "Freight train:
\n" ); document.write( "Rate = r - 10 = 25 - 10 = 15 \n" ); document.write( "

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