document.write( "Question 1175373: What is the probability that I get at least 3 aces from a hand of 5 cards in a deck of 52 cards ? \n" ); document.write( "
Algebra.Com's Answer #800989 by Edwin McCravy(20055)\"\" \"About 
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document.write( "Case 1.  The hand contains 3 aces and 2 non-aces.\r\n" );
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document.write( "There are 4 aces in the deck so there are C(4,3) = 4 ways to pick the 3 aces.\r\n" );
document.write( "There are 48 non-aces in the deck, so you can pick the two non-aces\r\n" );
document.write( "C(48,2)=1128 ways.\r\n" );
document.write( "That's C(4,3)C(48,2) = (4)(1128) = 4512 ways.\r\n" );
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document.write( "Case 2.  The hand contains all 4 aces and 1 non-ace.\r\n" );
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document.write( "There are 4 aces in the deck so there is C(4,4) = 1 way to pick all 4 aces.\r\n" );
document.write( "There are 48 non-aces in the deck, so you can pick the one non-ace C(48,1) = 48\r\n" );
document.write( "ways.\r\n" );
document.write( "That's C(4,4)C(48,1) = (1)(48) = 48 ways.\r\n" );
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document.write( "Add them together: 4512+48 = 4560 ways.\r\n" );
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document.write( "Edwin
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