document.write( "Question 1175368: A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 30% and the third contains 50%. They want to use all three solutions to obtain a mixture of 96 liters containing 35% acid, using 3 times as much of the 50% solution as the 30% solution. How many liters of each solution should be used? \n" ); document.write( "

Algebra.Com's Answer #800976 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "SOLUTION        VOLUME         PURE\r\n" );
document.write( "  15%            96-4v       0.15(96-4v)\r\n" );
document.write( "  30%             v          0.3v\r\n" );
document.write( "  50%            3v          0.5*3v\r\n" );
document.write( "TOTAL            96          0.35*96\r\n" );
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\n" ); document.write( "Simplify and solve for v:
\n" ); document.write( " $\"0.15%2896-4v%29%2B0.3v%2B0.5%2A3v=0.35%2A96\"$ \n" ); document.write( "

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