document.write( "Question 1175370: A movie theater has a seating capacity of 361. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $ 2614, How many children, students, and adults attended? \n" ); document.write( "

Algebra.Com's Answer #800975 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "A movie theater has a seating capacity of 361. The theater charges $5.00 for children,
\n" ); document.write( "$7.00 for students, and $12.00 of adults. There are half as many adults as there are children.
\n" ); document.write( "If the total ticket sales was $ 2614, How many children, students, and adults attended?
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document.write( "x adults\r\n" );
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document.write( "2x children\r\n" );
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document.write( "and (361 - x - 2x) = (361-3x) students (the rest . . . )\r\n" );
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document.write( "Total money equation\r\n" );
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document.write( "    12x + 5*(2x) + 7*(361-3x) = 2614   dollars\r\n" );
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document.write( "Simplify and solve\r\n" );
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document.write( "    12x + 10x - 21x = 2614 - 7*361\r\n" );
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document.write( "           x        =     87\r\n" );
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document.write( "ANSWER.  87 adults;  2*87 = 174 children  and the rest  361-87 - 174 = 100 are students.\r\n" );
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document.write( "CHECK.   87*12 + 5*174 + 7*100 = 2614 dollars, in total.    ! Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "Notice that I solved the problem using only one equation and only one single unknown.\r
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\n" ); document.write( "\n" ); document.write( "It is how this problem SHOULD be solved (!)\r
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\n" ); document.write( "\n" ); document.write( "Also, notice that the capacity of the theater is IRRELEVANT to this problem.\r
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\n" ); document.write( "\n" ); document.write( "We only should know (instead of the total capacity) the total number of SOLD TICKETS.\r
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