document.write( "Question 1175331: Toss a 4 coins 15 times and write your outcomes, what will be the probability of getting
\n" ); document.write( "At least 3 head
\n" ); document.write( "At most 2 head
\n" ); document.write( "Exactly 1 head
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #800955 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "Hi\r\n" );
document.write( "\r\n" );
document.write( "Binomial Distribution:  p = 1/2 and q = 1/2  n = 4 (coins)\r\n" );
document.write( "Using Calculator (TI instructions given here)\r\n" );
document.write( "An inexpensive, easy to use  Casio fx-115 ES plus works similarly\r\n" );
document.write( "\r\n" );
document.write( "P(At least 3 head)= P(x ≥ 3) =   1- P(x ≤ 2) \r\n" );
document.write( "        1 - binomcdf(4,.5,2) = 1 - .6875 = .3125  0r 31.25%\r\n" );
document.write( "\r\n" );
document.write( "P(At most 2 head) = P(x ≤ 2) = binomcdf(4,.5,2) =.6875  0r 68.75%\r\n" );
document.write( "\r\n" );
document.write( "P(Exactly 1 head) = P(x=1) = binompdf(4,.5,1) = .25 0r 25%\r\n" );
document.write( "\r\n" );
document.write( "One would expect, over the 15 times of tossing the 4 coins..\r\n" );
document.write( "on an average... the above percentages would hold true.\r\n" );
document.write( "\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );