document.write( "Question 1175344: Let A is event a child is infected with ascariasis, and G be event a child infected with giardiasis. Suppose P(A)= .30, P(G)=.25 and P(AnG)=.13.
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document.write( "Then what is the probability that s child randomly selected will test negative for these intestinal parasite?
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Algebra.Com's Answer #800940 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It seems to me that to be infected is different event as to be tested positively;\r \n" ); document.write( "\n" ); document.write( "as well as to be not infected is different event as to be tested negatively.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, if in your post/problem you try to use professional terminology, then do it consistently.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Now, if to forget about these details, the probability to be infected at least one one of \"these intestinal parasites\" is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " P(A or B) = 0.3 + 0.25 - 0.13 = 0.42.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The probability do not be infected is the COMPLEMENT to it, i.e.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 1 - 0.42 = 0.58. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |