document.write( "Question 109916: I need to solve this problem and show solution used....HELP!!!!\r
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document.write( "The length of a rectangle is 2 in more than twice its width . If the perimeter of the rectangle is 34 in find the dimensions of the rectangle.\r
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document.write( "thanks alot
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document.write( "Heather \n" );
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Algebra.Com's Answer #80092 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+2 \n" ); document.write( "PERIMETER=2L+2W \n" ); document.write( "34=2(2W+2)+2W \n" ); document.write( "34=4W+4+2W \n" ); document.write( "6W=34-4 \n" ); document.write( "6W=30 \n" ); document.write( "W=30/6 \n" ); document.write( "W=5 ANSWER. \n" ); document.write( "L=2*5+2 \n" ); document.write( "L=10+2 \n" ); document.write( "L=12 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( "2*12+2*5=34 \n" ); document.write( "24+10=34 \n" ); document.write( "34=34 \n" ); document.write( " |