document.write( "Question 109916: I need to solve this problem and show solution used....HELP!!!!\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 2 in more than twice its width . If the perimeter of the rectangle is 34 in find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "thanks alot
\n" ); document.write( "Heather
\n" ); document.write( "

Algebra.Com's Answer #80092 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
L=2W+2
\n" ); document.write( "PERIMETER=2L+2W
\n" ); document.write( "34=2(2W+2)+2W
\n" ); document.write( "34=4W+4+2W
\n" ); document.write( "6W=34-4
\n" ); document.write( "6W=30
\n" ); document.write( "W=30/6
\n" ); document.write( "W=5 ANSWER.
\n" ); document.write( "L=2*5+2
\n" ); document.write( "L=10+2
\n" ); document.write( "L=12 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "2*12+2*5=34
\n" ); document.write( "24+10=34
\n" ); document.write( "34=34
\n" ); document.write( "
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