document.write( "Question 1175298: Margin of Error for Proportions
\n" ); document.write( "1. A survey was given to a random sample of 125 voters in the United States to ask about their preference for a presidential candidate. Of those surveyed, 76% of the people said they preferred Candidate A. At the 95% confidence level, what is the margin of error for this survey expressed as a percentage to the nearest tenth? (Do not write \pm±).\r
\n" ); document.write( "\n" ); document.write( "Confidence Intervals for Proportions
\n" ); document.write( "2. A survey was given to a random sample of 60 voters in the United States to ask about their preference for a presidential candidate. Of those surveyed, 27 respondents said that they preferred Candidate A. Determine a 95% confidence interval for the proportion of people who prefer Candidate A, rounding values to the nearest thousandth. (,) \n" ); document.write( "

Algebra.Com's Answer #800888 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Hi\r\n" );
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document.write( "ME = \r\n" );
document.write( "ME =  = .075\r\n" );
document.write( "CI: (.685 , .835 )\r\n" );
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document.write( "2) mean= 27/60= .45\r\n" );
document.write( "ME =   = .126 \r\n" );
document.write( "CI: (.324 , .576) \r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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