document.write( "Question 1175286: A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 25% and the third contains 70%. They want to use all three solutions to obtain a mixture of 60 liters containing 45% acid, using 2 times as much of the 70% solution as the 25% solution. How many liters of each solution should be used? \n" ); document.write( "
Algebra.Com's Answer #800877 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi\r\n" );
document.write( " 60 liters \r\n" );
document.write( " 45% acid, using 2 times as much of the 70% solution as the 25% solution. \r\n" );
document.write( " .15(60L - 3x)) + .25(x)  + .70(2x) = .45(60L)\r\n" );
document.write( " .15(60L) - .45x  + .25(x)  + 1.4x   = .45(60L) \r\n" );
document.write( "                                  x = .30(60L)/1.2 = 15L of the 25% solution\r\n" );
document.write( " 15L of the 25% solution, 30L of the 70% solution & 15L of 15% solution\r\n" );
document.write( "           27=27 checks\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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