document.write( "Question 1175264: Please help me find the original fraction- The denominator of a fraction is five more than twice the numerator.
\n" ); document.write( "If both numerator and denominator are decreased by two,
\n" ); document.write( "the simplified result is 1/3. Find the original fraction. \n" ); document.write( "

Algebra.Com's Answer #800856 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi\r\n" );
document.write( "The denominator of a fraction is five more than twice the numerator.\"n\"\r\n" );
document.write( "n/(2n+5)\r\n" );
document.write( "If both numerator and denominator are decreased by two\r\n" );
document.write( "(n-2)/(2n+3) = 1/3\r\n" );
document.write( "3(n-2) = 2n+3\r\n" );
document.write( "n = 9  and the denominator is 23   \r\n" );
document.write( " Original fraction is :  9/23\r\n" );
document.write( "7/21 = 1/3  checks\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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