document.write( "Question 109890: solve the system by additio or substitution
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document.write( "3x+6y=0
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document.write( "x= 2/3\r
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document.write( "I have no idea how to work this problem with a fraction. Please help. \n" );
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Algebra.Com's Answer #80083 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 3x+6y=0 \n" ); document.write( "x= 2/3 \n" ); document.write( ": \n" ); document.write( "Just substitute 2/3 for x in the 1st equation, and find y \n" ); document.write( ": \n" ); document.write( "3( \n" ); document.write( ": \n" ); document.write( "The 3's cancel and you have; \n" ); document.write( "2 + 6y = 0 \n" ); document.write( "6y = -2 \n" ); document.write( "y = \n" ); document.write( "y = \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the original equation: \n" ); document.write( "3( \n" ); document.write( " 2 - 2 = 0 \n" ); document.write( " |