document.write( "Question 1175232: If sec X = 3 and the terminal side x does not lie on the first quadrant, find the
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Algebra.Com's Answer #800821 by Edwin McCravy(20063)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We have a conflict of notation.  We can't call the x-axis if we call the angle\r\n" );
document.write( "x also.  So I will call the angle capital X and the x-axis by small x.

\n" ); document.write( "If sec X = 3 and the terminal side x does not lie on the first quadrant, find the
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document.write( "We will consider 3 as the fraction 3/1.\r\n" );
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document.write( "Since the secant is positive in the first and fourth quadrant and it does not\r\n" );
document.write( "lie in the first quadrant, then it lies in the fourth quadrant.\r\n" );
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document.write( "We draw a right triangle with an angle in Q4, and remember that the secant\r\n" );
document.write( "is the hypotenuse over the adjacent (or the r over the x). So we put the\r\n" );
document.write( "numerator of 3/1, which is 3, on the hypotenuse (or the r) and the denominator\r\n" );
document.write( "of 3/1, which is 1, on the adjacent side, (or the x). Then we calculate the\r\n" );
document.write( "opposite side (or the y) by using the Pythagorean theorem:\r\n" );
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document.write( "Since it's Q4 we know that y is negative, so we put -2√2 on the opposite\r\n" );
document.write( "side (y):\r\n" );
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document.write( "So now we know that\r\n" );
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document.write( "\"sin%28X%29=opposite%2Fhypotenuse+=+y%2Fr=%28-2sqrt%282%29%29%2F3\"\r\n" );
document.write( "\"cos%28X%29=hypotenuse%2Fopposite+=+x%2Fr=1%2F3\"\r\n" );
document.write( "\"tan%28X%29=hypotenuse%2Fopposite+=+y%2Fx=%28-2sqrt%282%29%29%2F1=-2sqrt%282%29\"\r\n" );
document.write( "\"sec%28X%29=hypotenuse%2Fopposite+=+r%2Fx=given=3\"\r\n" );
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document.write( "Edwin
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