document.write( "Question 109879: Factor completely. b2 – ab – 6a2 \n" ); document.write( "
Algebra.Com's Answer #80079 by jim_thompson5910(35256)\"\" \"About 
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First off, what two numbers multiply to -6 (the last coefficient) but add to -1 (the middle coefficient)? It turns out that -3 and 2 multiply to -6 but add to -1.\r
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\n" ); document.write( "\n" ); document.write( "So replace the middle term of \"b%5E2-ab-6a%5E2\" with \"-3ab%2B2ab\" to get \"b%5E2-3ab%2B2ab-6a%5E2\" \r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"b%5E2-3ab%2B2ab-6a%5E2\" by grouping\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%5E2-3ab%29%2B%282ab-6a%5E2%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"b%28b-3a%29%2B2a%28b-3a%29\" Factor out the GCF of \"b\" out of the first group. Factor out the GCF of \"2a\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%2B2a%29%28b-3a%29\" Since we have a common term of \"b%2B-3a\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"b%5E2-3ab%2B2ab-6a%5E2\" factors to \"%28b%2B2a%29%28b-3a%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "This means \"b%5E2-ab-6a%5E2\" factors to \"%28b%2B2a%29%28b-3a%29\" also\r
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\n" ); document.write( "\n" ); document.write( "Notice how \"%28b%2B2a%29%28b-3a%29\" foils back to \"b%5E2-3ab%2B2ab-6a%5E2\" which simplifies to \"b%5E2-ab-6a%5E2\". So this verifies our answer.
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