document.write( "Question 1175204: Rate time distance Practice problem\r
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\n" ); document.write( "\n" ); document.write( "Chelsea is 138 miles away from Laura. They are traveling towards each other. If Laura travels 5 mph faster than Chelsea and they meet after 6 hours, how fast was each traveling?\r
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\n" ); document.write( "\n" ); document.write( "Chelsea is traveling_______mph.\r
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\n" ); document.write( "\n" ); document.write( "Laura is traveling_________mph.\r
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\n" ); document.write( "\n" ); document.write( "_______hours at 15 mph\r
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\n" ); document.write( "\n" ); document.write( "_______hours at 4 mph
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Algebra.Com's Answer #800748 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Chelsea's distance traveled + Laura’s distance traveled = \"138\" miles\r
\n" ); document.write( "\n" ); document.write( "\"t=6+\"hours
\n" ); document.write( "\"d=rt\"\r
\n" ); document.write( "\n" ); document.write( "let Chelsea's rate be \"r\" and Laura’s rate be \"r%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"6%2Ar+%2B+6%2A%28r%2B5%29+=+138\"
\n" ); document.write( "\"6r+%2B+6r%2B30+=+138\"
\n" ); document.write( "\"12r=+138-30\"
\n" ); document.write( "\"12r=+108\"
\n" ); document.write( "\"r=+108%2F12\"
\n" ); document.write( "\"r=+9\"
\n" ); document.write( "=>Chelsea was traveling \"9%28mil%2Fh%29\"\r
\n" ); document.write( "\n" ); document.write( "then Laura’s rate was \"r%2B5=9%2B5=14%28mil%2Fh%29\"\r
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