document.write( "Question 1175139: How do I write a linear function f with the given values
\n" ); document.write( "A. f(0) = 4,f(5) = 19
\n" ); document.write( "B. f (-5) = 32,f(0) = 22
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Algebra.Com's Answer #800693 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "write a linear function f with the given values\r
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\n" ); document.write( "\n" ); document.write( "A.
\n" ); document.write( "\"f%28x%29+=+ax%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "if \"f%280%29+=+4\" means for \"x=0\" \"y=4\"
\n" ); document.write( "\"4=+a%2A0%2Bb\"
\n" ); document.write( "\"b=4\"\r
\n" ); document.write( "\n" ); document.write( "if f(5) = 19
\n" ); document.write( "\"19=+a%2A5%2B4\"
\n" ); document.write( "\"19-4=+5a\"
\n" ); document.write( "\"15=+5a\"
\n" ); document.write( "\"a=3\"\r
\n" ); document.write( "\n" ); document.write( "equation is: \"f%28x%29+=+3x%2B4\"\r
\n" ); document.write( "\n" ); document.write( "B.
\n" ); document.write( "use another way to find equation\r
\n" ); document.write( "\n" ); document.write( "if \"f+%28-5%29+=+32\", that is point (\"x%5B1%5D\",\"y%5B1%5D\")=(\"-5\",\"32\")\r
\n" ); document.write( "\n" ); document.write( "if \"f%280%29+=+22\", that is point (\"x%5B2%5D\",\"y%5B2%5D\")=(\"0\",\"22\")=> this point is y-intercept, so \"b=22\"\r
\n" ); document.write( "\n" ); document.write( "now find a slope \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"a=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=%2822-32%29%2F%280-%28-5%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=-10%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"a=-2\"\r
\n" ); document.write( "\n" ); document.write( "equation is: \"f%28x%29+=+-2x%2B22\"\r
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