document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107675>Question 107675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary and the measure of one of them is 20% less than three times the measure of the other. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80067 by </B><A HREF=/tutors/aboutme.mpl?userid=richmusick><B>richmusick(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richmusick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=180 OR X=180-Y<BR>\n" );
document.write( "X=3Y - .2(3Y)<BR>\n" );
document.write( "X=3Y - .6Y<BR>\n" );
document.write( "X=2.4Y<BR>\n" );
document.write( "2.4Y + Y = 180<BR>\n" );
document.write( "3.4Y=180<BR>\n" );
document.write( "Y=180/3.4<BR>\n" );
document.write( "Y=53° FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "X+53°=180°<BR>\n" );
document.write( "X=180° - 53°<BR>\n" );
document.write( "X=127° FOR THE LARGER ANGLE.\r<BR>\n" );
document.write( "\n" );
document.write( "PROOF<BR>\n" );
document.write( "Y = 53°<BR>\n" );
document.write( "X = 2.4Y<BR>\n" );
document.write( "2.4(53) = 127° <BR>\n" );
document.write( "53° + 127°=180°<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );