document.write( "Question 1175038: a businessman invests an amount of Php 300,000 in a bank,the simple interest is Php 365,000 for 5 years. what interest rate is applied by the bank?
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Algebra.Com's Answer #800621 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"I+=365000\"
\n" ); document.write( "\"P=300000\"
\n" ); document.write( "\"t=5+\"years\r
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\n" ); document.write( "\n" ); document.write( "\"I+=+A+-+P\"\r
\n" ); document.write( "\n" ); document.write( "total amount is:\r
\n" ); document.write( "\n" ); document.write( "\"A=I+%2BP\"
\n" ); document.write( "\"A=365000%2B300000\"
\n" ); document.write( "\"A=665000\"\r
\n" ); document.write( "\n" ); document.write( "to find interest rate, use \r
\n" ); document.write( "\n" ); document.write( "\"A+=+P%281+%2B+rt%29\"\r
\n" ); document.write( "\n" ); document.write( "\"665000+=+300000%281+%2B+r%2A5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"665000%2F300000=%281+%2B+r%2A5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"133%2F60=1+%2B+5r\"\r
\n" ); document.write( "\n" ); document.write( "\"133%2F60-1=5r\"\r
\n" ); document.write( "\n" ); document.write( "\"73%2F60=5r\"\r
\n" ); document.write( "\n" ); document.write( "\"r=73%2F300\"\r
\n" ); document.write( "\n" ); document.write( "\"r=0.2433333\"=>as decimal\r
\n" ); document.write( "\n" ); document.write( "interest rate is:\r
\n" ); document.write( "\n" ); document.write( "\"R=100r\"
\n" ); document.write( "\"R=24.33333\"%\r
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