document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1175051>Question 1175051</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that total carbohydrate intake in 12-14 years old males is normally distributed with mean 124 g/1000 cal and standard deviation of 20 g / 1000cal.<BR>\n" );
document.write( "a. What percent of boys in this age range have carbohydrate intake above 140 g/ 1000 cal?<BR>\n" );
document.write( "b. What is the probability that a sample of 35 boys have a mean carbohydrate intake of greater than 120 g /100 cal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #800606 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=800606\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "so for a (140-124)/20 or z > 0.8<BR>\n" );
document.write( "that probability is 0.2119 from the calculator 2ndVARS ENTER 2 normalcdf(.8,6) ENTER. The 6 is the std deviations to essentially 100%. Some use 1E99, 6 works, and it is easier. 7 would and 8 would, but 5 has some error.<BR>\n" );
document.write( "-<BR>\n" );
document.write( "for b z=(x bar-mean(/sigma/sqrt(n), since std error of sample is sigma/sqrt(n).<BR>\n" );
document.write( "This is z> (120-124)/20/sqrt(35) or > -4*sqrt(35)/20= -1.18 and that probability is 0.8810 </SPAN>\n" );
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