document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1175075>Question 1175075</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An investment decreases by 50% over an 8-year period.<BR>\n" );
document.write( "At what effective annual percent rate does it decrease? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #800603 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=800603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is (1-x)^8=0.50<BR>\n" );
document.write( "Can do it by logs or by the 8th root of both sides, since we have calculators. <BR>\n" );
document.write( "0.50^(1/8)=0.9170<BR>\n" );
document.write( "1-x=0.9170<BR>\n" );
document.write( "x=0.0830 or 8.3% annual rate of decrease. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );