document.write( "Question 1175071: Let be a standard normal random variable. Use the calculator provided, or this table, to determine the value of c. P(-c≤Z≤c)=0.9412
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document.write( "Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.
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Algebra.Com's Answer #800601 by ewatrrr(24785) You can put this solution on YOUR website! \r\n" ); document.write( "Hi \r\n" ); document.write( "(1 - .9412)/2 = .0294\r\n" ); document.write( "invNorm(.0294) = 1.8897\r\n" ); document.write( "P(-1.8897 ≤ z ≤1.8897) = 0.9412\r\n" ); document.write( "\r\n" ); document.write( "Wish You the Best in your Studies.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |