document.write( "Question 1174577: Given a value of one circular function and a sign of another function (or the quadrant where the angle lies), find the value of the indicated function. (Complete all solutions)\r
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Algebra.Com's Answer #800523 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
[a] sin θ=1/2, θ in Q1; cos θ
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document.write( "We draw a right triangle with an angle in Q1, and remember that the sine is the\r\n" );
document.write( "opposite over the hypotenuse (or the y over the r). So we put the numerator of\r\n" );
document.write( "1/2, which is 1, on the opposite side (or the y) and the denominator of 1/2,\r\n" );
document.write( "which is 2, on the hypotenuse, (or the r). Then we calculate the adjacent using\r\n" );
document.write( "the Pythagorean theorem:\r\n" );
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document.write( "Since it's Q1 we know that x is positive, so we put √3 on the adjacent x:\r\n" );
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document.write( "So now we know that\r\n" );
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document.write( "\"cos%28theta%29=adjacent%2Fhypotenuse+=+x%2Fr=sqrt%283%29%2F2\"\r\n" );
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[b] cos θ=3/5, θ in Q4; csc θ
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document.write( "We draw a right triangle with an angle in Q4, and remember that the cosine is\r\n" );
document.write( "the adjacent over the hypotenuse (or the x over the r). So we put the numerator\r\n" );
document.write( "of 3/5, which is 3, on the adjacent side (or the x) and the denominator of 3/5,\r\n" );
document.write( "which is 5, on the hypotenuse, (or the r). Then we calculate the opposite using\r\n" );
document.write( "the Pythagorean theorem:\r\n" );
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document.write( "Since it's Q4 we know that y is negative, so we put -4 on the opposite y:\r\n" );
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document.write( "So now we know that\r\n" );
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document.write( "\"csc%28theta%29=hypotenuse%2Fopposite+=+r%2Fy=5%2F%28-4%29=-5%2F4\"\r\n" );
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document.write( "See if you can do the other two by yourself. [c] is in Q2 and [d] is in Q1\r\n" );
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document.write( "Edwin
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