document.write( "Question 1174577: Given a value of one circular function and a sign of another function (or the quadrant where the angle lies), find the value of the indicated function. (Complete all solutions)\r
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document.write( "[a] sin θ=1/2, θ in Q1; cos θ
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document.write( "[b] cos θ=3/5, θ in Q4; csc θ
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document.write( "[c] sin θ=3/7, sec θ < 0; tan θ
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document.write( "[d] cot θ=2/9, cos θ > 0; csc θ \n" );
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Algebra.Com's Answer #800523 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! [a] sin θ=1/2, θ in Q1; cos θ \r\n" ); document.write( "We draw a right triangle with an angle in Q1, and remember that the sine is the\r\n" ); document.write( "opposite over the hypotenuse (or the y over the r). So we put the numerator of\r\n" ); document.write( "1/2, which is 1, on the opposite side (or the y) and the denominator of 1/2,\r\n" ); document.write( "which is 2, on the hypotenuse, (or the r). Then we calculate the adjacent using\r\n" ); document.write( "the Pythagorean theorem:\r\n" ); document.write( "\r\n" ); document.write( "[b] cos θ=3/5, θ in Q4; csc θ \r\n" ); document.write( "We draw a right triangle with an angle in Q4, and remember that the cosine is\r\n" ); document.write( "the adjacent over the hypotenuse (or the x over the r). So we put the numerator\r\n" ); document.write( "of 3/5, which is 3, on the adjacent side (or the x) and the denominator of 3/5,\r\n" ); document.write( "which is 5, on the hypotenuse, (or the r). Then we calculate the opposite using\r\n" ); document.write( "the Pythagorean theorem:\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |