document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=109825>Question 109825</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 2005, Dan raced his car 500 miles. His rate was 157.603 mph. What was his time (to the nearest thousandth of an hour)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80052 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the distance formula: Distance = (Rate)(Time)<BR>\n" );
document.write( "500 miles = (157.603)(t) [plug-in the values]<BR>\n" );
document.write( "500/157.603=157.603t/157.603 [isolate the t-term]<BR>\n" );
document.write( "3.172528=t <BR>\n" );
document.write( "or<BR>\n" );
document.write( "t=3.173 hours<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check by plugging all of the variables back into the original equation and solve:<BR>\n" );
document.write( "D=rt<BR>\n" );
document.write( "500=(157.603)(3.173)<BR>\n" );
document.write( "500=500.074 [close enough] </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );