document.write( "Question 1174984: Find a three-digit number such that the hundreds’ digit minus the tens’ digit is 1, the tens’ digit
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document.write( "minus the units’ digit is 1, and the sum of the digits is 15. \n" );
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Algebra.Com's Answer #800502 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Let x be the \"ones\" digit.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the \"tens\" digit is (x+1) and the \"hundreds\" digit is ((x+1)+1) = (x+2).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From the condition,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x + (x+1) + (x+2) = 15,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "which implies\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 3x = 15 - 3 = 12\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x = 12/3 = 4.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. The number is 654.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The problem is SO SIMPLE that the solution requires only several lines.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |