document.write( "Question 1174983: 1. The mean serum cholesterol level in a certain population of normal healthy men
\n" ); document.write( "is 240 mg/dl and the standard deviation is 40 mg/dl. A clinical researcher
\n" ); document.write( "interested in comparing cholesterol levels in this healthy population with those
\n" ); document.write( "in men with coronary artery disease measured serum cholesterol level in a
\n" ); document.write( "random sample of 100men who had undergone coronary bypass surgery during
\n" ); document.write( "the preceding two year period. The mean serum cholesterol level for sampling
\n" ); document.write( "was 260 mg/dl
\n" ); document.write( "A. What is the 95% confidence interval estimate of the mean cholesterol level for
\n" ); document.write( "all men undergoing bypass surgery? Assume that the standard deviation of
\n" ); document.write( "serum cholesterol measurement for this population is the same as that of the
\n" ); document.write( "healthy population ( i.e., 40mg/dl)
\n" ); document.write( "B. Based on this estimate, can the researcher conclude that the mean serum
\n" ); document.write( "cholesterol of men undergoing coronary bypass surgery differs from that of
\n" ); document.write( "healthy men?
\n" ); document.write( "2. Among 200 patients at a Tikur Anbessa hospital.
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Algebra.Com's Answer #800494 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "I'll do the first problem to get you started.
\n" ); document.write( "You should only post one question at a time please.\r
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\n" ); document.write( "Part A\r
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\n" ); document.write( "\n" ); document.write( "For the population of men undergoing the surgery, we have
\n" ); document.write( "xbar = 260 mg/dl = sample mean, used to estimate population mean (mu)
\n" ); document.write( "sigma = 40 mg/dl = population standard deviation
\n" ); document.write( "n = 100 = sample size\r
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\n" ); document.write( "\n" ); document.write( "At 95% confidence, the z critical value is roughly z = 1.960
\n" ); document.write( "We're using the standard normal z distribution because we know the population standard deviation sigma.\r
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\n" ); document.write( "\n" ); document.write( "The lower bound L of the confidence interval is:
\n" ); document.write( "L = xbar - z*sigma/sqrt(n)
\n" ); document.write( "L = 260 - 1.960*40/sqrt(100)
\n" ); document.write( "L = 260 - 7.84
\n" ); document.write( "L = 252.16\r
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\n" ); document.write( "\n" ); document.write( "The upper bound U is
\n" ); document.write( "U = xbar + z*sigma/sqrt(n)
\n" ); document.write( "U = 260 + 1.960*40/sqrt(100)
\n" ); document.write( "U = 260 + 7.84
\n" ); document.write( "U = 267.84\r
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\n" ); document.write( "\n" ); document.write( "The 95% confidence interval to estimate the mean population (mu) of the cholesterol level of the men undergoing surgery is (252.16, 267.84)
\n" ); document.write( "We are 95% confident that mu is somewhere in the interval (252.16, 267.84)\r
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\n" ); document.write( "\n" ); document.write( "We can express that interval as 252.16 < mu < 267.84\r
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\n" ); document.write( "\n" ); document.write( "Part B\r
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\n" ); document.write( "\n" ); document.write( "Yes we can conclude that the mean serum cholesterol for the men undergoing bypass surgery differs from the healthy men.
\n" ); document.write( "This is because the interval 252.16 < mu < 267.84 does not contain mu = 240. This value is to the left of the lower bound 252.16\r
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\n" ); document.write( "\n" ); document.write( "Since mu = 240 is not in the interval 252.16 < mu < 267.84, this means there's no way mu can be equal to 240 for the population of men undergoing surgery. \r
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\n" ); document.write( "\n" ); document.write( "In other words, if A and B represent the population means for the healthy men vs the men undergoing surgery, then we can say:
\n" ); document.write( "A = 240
\n" ); document.write( "B = some value between 252.16 and 267.84
\n" ); document.write( "clearly we can see that B = 240 is not possible and B > A and B > 252.16\r
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