document.write( "Question 1174949: y = (a - x) / (2a - x)\r
\n" ); document.write( "\n" ); document.write( "Solve for x in terms of y and a.\r
\n" ); document.write( "\n" ); document.write( "Not sure how to solve.
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Algebra.Com's Answer #800463 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "\"Solve for x in terms of y and a\" means that your teacher wants you to get x all by itself, and have some expression with y's and/or a's on the other side.\r
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\n" ); document.write( "\n" ); document.write( "Currently we have x on the right side and it's buried in a somewhat complicated fraction.\r
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\n" ); document.write( "\n" ); document.write( "What we can do is multiply both sides by (2a-x) to move that term over. Then we apply distribution.\r
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\n" ); document.write( "\n" ); document.write( "y = (a-x)/(2a-x)
\n" ); document.write( "y(2a-x) = a-x
\n" ); document.write( "y*2a+y(-x) = a-x
\n" ); document.write( "2ay - xy = a-x\r
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\n" ); document.write( "\n" ); document.write( "After doing those steps, let's get all of the terms that have 'x' in them to one side. Everything else gets to the other side.\r
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\n" ); document.write( "\n" ); document.write( "2ay - xy = a-x
\n" ); document.write( "2ay - xy+x = a-x+x
\n" ); document.write( "2ay - xy+x = a
\n" ); document.write( "2ay - xy+x-2ay = a-2ay
\n" ); document.write( "-xy+x = a-2ay
\n" ); document.write( "x-xy = a-2ay\r
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\n" ); document.write( "\n" ); document.write( "Note how we can factor out x from the left side. We're using the distributive property. After factoring, divide both sides by (1-y) to fully isolate x\r
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\n" ); document.write( "\n" ); document.write( "x-xy = a-2ay
\n" ); document.write( "x(1-y) = a-2ay
\n" ); document.write( "x = (a-2ay)/(1-y)\r
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\n" ); document.write( "\n" ); document.write( "We've reached our goal of getting x all by itself on one side. The other side consists of some combination of 'a's and 'y's in which we are applying arithmetic operations to them.
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